Feedback and Opinions on the New Prestige Ranks
This topic contains 29 replies, has 10 voices, and was last updated by 
Beijimon 9 years, 3 months ago.
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AnonymousAlright, be prepared to read a lot of maths…
Now, we all know that the new prestige ranks are just released… However, they are more expensive than expected. These ranks are made by banana and he decided to double the prices, but didn’t know that they get higher exponentially, because dy/dx e^x = e^x.
Now, everyone is asking for the equation of the prices… Here it is (Its an Exponential Function):
y=kb^x
In this context, y is the Full price of the Entire Prestige, k is the Full price of the normal ranks, b is a Constant Multiplier and x is your Prestige Number… Calculations shows that k = $57,447,000 and b=2 (from Banana’s doubles). This is the resultant equation:
y=57,447,000(2^x)
This means that from Rank A to P-10-Free, it costs $117,594,009,000 and that is way too much -.-, which isn’t going to be accepted by most players…
Now, people can say that ‘Eh, Prestige Picks are so useful’. That isn’t true, because the Fortune Enchantment is an inverse Exponential Function…
This is the equation to calculate your increase of loot:
1/(n+2) x n(n+1)/2 x 100% = (n^2+n)/(2n+4) x 100%, where n is your Fortune Enchantment Level.
(All to 3 Significant Figures)
P1 is Fortune 5, sub n=5 into the equation and you get 214% increase of loot.
P2 is Fortune 6, sub n=6 into the equation and you get 262% increase of loot.
P3 is Fortune 7, sub n=7 into the equation and you get 311% increase of loot.
P4 is Fortune 8, sub n=8 into the equation and you get 360% increase of loot.
P5 is Fortune 9, sub n=9 into the equation and you get 409% increase of loot.
P6 is Fortune 10, sub n=10 into the equation and you get 458% increase of loot.
P7 is Fortune 11, sub n=11 into the equation and you get 508% increase of loot.
P8 is Fortune 12, sub n=12 into the equation and you get 557% increase of loot.
P9 is Fortune 13, sub n=13 into the equation and you get 607% increase of loot.
P10 is Fortune 14, sub n=14 into the equation and you get 656% increase of loot.
As you can see, there is really no difference between each Prestige Pickaxes, hence this makes the prestige ranks way too hard.
So here is the question:
What Constant Multiplier do you want the prices to be multiplied by?
Mathematically this is the more logical question:
What value of b, instead of 2, do you want it to be?
Please post your answers below, and explain why that should be the ideal multiplier…
AnonymousEruptional Bump!
Good Late Quarter Vaporeon o’ Clock People!
Anonymous-.-, Clearly all of us are trying to reduce the prestige prices, its way too expensive, until hardcore wont even come because nobody bothers about P10 anymore…
You will get new perks everytime you take a new prestige level. The perks will be much helpful for you to rankup.
AnonymousAs if they are proportionate…
AnonymousAlso, I want the entire list of rankup prices posted here…
Normally I’d say ‘melee stop acting smart with your math’, but now I have to agree. The price gets too high.
-> Lower multiplier, less prestiges, or no ‘P1/2/3/…/10’ at all. I knew this would happen… -.-😛 the only prices that bug me are the prices from a-l… I’m having trouble even getting to I! But removing the requirement of having to rank up from a-l should potentially reduce the amount needed to rank from p1-p10…
the price doubles each time, and thats how it should be. Your not meant to RUSH through the prestiges crazy fast! This is NOT OP prison.
the price doubles each time, and thats how it should be. Your not meant to RUSH through the prestiges crazy fast! This is NOT OP prison.
I don’t think anyone will go past P4 or P5, I mean, who the heck would work for 110 billion on the same mine that made them only thousands and millions?
AnonymousWhat Rogue said, no one is going to mine out $110 Billion worth of stuffs in a mine that is worth only Millions…
Also, Update from Clockspeed, the equation finally changed:
If you want to Prestige from P(y) to P(x), the price is f(x) = (Normal Price) * (x + 1) or ($57,447,000)(x + 1)
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